commutation rectifier

single phase two diode rectifier. LR output. time constant = L/R >> 1/f.
D2 is free wheeling diode.

average output current = Vr/R = 2.5/100 = 0.025A.

adding L3, commutation takes place.

L3 << L1, output current remains constant, the blur in output happens when commutation takes place.

for ideal case, the firing angle = cos-1(1-2*pi*f*L1*Iout/Vin) ~= 1degree.

in reality, the firing angle is much larger, the clear trace in the diagram is produced in the period of commutation, because during commutation both diode are on; therefore, Voltage at port 2 of L3 is 0v. VL3 = Vin.